· the nitrate and the natrium ions. This tells you that you can expect the ph of the resulting solution to be … The gas would interact … Na_2co_3(aq) + 2agno_3(aq) rarr ag_2co_3(s)darr + 2nano_3(aq) the net ionic equation is: 2ag^(+) + co_3^(2-) rarr … Hydroxide anion, −oh, has a unit negative charge. · these are ostensibly acid-base reactions. Thats a silly way to say carbon dioxide! · lithium is a group 1 metal and commonly forms a m + ion. Start with the equation: · the cyanate anions will react with water to form isocyanic acid, hnco, and hydroxide anions, oh−. The molarity of the acid is 1. 434. · a good leaving group has to be able to part with its electrons easily enough, so typically, it must be a strong acid or weak base relative to other substituents on the same … Nh_4^+ +ho^(-) rarr nh_3(aq) + h_2o(l) for methanol, the acid base reaction would proceed. 2hno_ (3 (aq))+ca (oh)_ (2 (aq))rarrca (no_3)_ (2 (aq))+2h_2o_ ( (l)) this tells us that 2 moles of hno_3. · because n aoh → n a+ + oh − and n i2+ + 2oh −→n i(oh)2 total mols of n aoh: · mg (oh)_2 now we know that hydroxides are salts of ho^-, and some metal ion. 60ml ⋅ 0. 45m ol/l = 27mm ol of n aoh (dont forget the m for milli=one thousandth) this … · could a buffered solution be made by mixing aqueous solutions of hcl and naoh? Now if the parent metal has an electronic configuration of 2:8:2, then there are 12 electrons, … Why isnt a mixture of a strong acid and its conjugate base considered a buffered … When they make music together, there is thus 1:1 stoichiometry … For ammonium we could write. Co_2(g)+ca(oh)_2(aq) rightleftharpoons ca^(2+)(aq)+h_2co_3(aq) may be wrong, but it seems reasonable.
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· the nitrate and the natrium ions. This tells you that you can expect the ph of the resulting solution to be … The gas...
